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Problem
Problem
Number of solutions of the equation
e
−
sin
2
x
=
tan
2
x
e^{-\sin^2 x} = \tan 2x
e
−
s
i
n
2
x
=
tan
2
x
in
[
0
,
10
π
]
[0, 10\pi]
[
0
,
10
π
]
is:
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