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Mathematics
Problem
Let
r
=
u
−
v
\mathbf{r}=\mathbf{u}-\mathbf{v}
r
=
u
−
v
where
u
\mathbf{u}
u
and
v
\mathbf{v}
v
are two non–zero vectors with magnitudes
∣
u
∣
=
a
|\mathbf{u}|=a
∣
u
∣
=
a
and
∣
v
∣
=
b
|\mathbf{v}|=b
∣
v
∣
=
b
. The angle between
u
\mathbf{u}
u
and
v
\mathbf{v}
v
is
θ
\theta
θ
(with
0
<
θ
<
π
0<\theta<\pi
0
<
θ
<
π
). a. (i) Prove that
∣
r
∣
2
=
a
2
+
b
2
−
2
a
b
cos
θ
|\mathbf{r}|^{2}=a^{2}+b^{2}-2ab\cos\theta
∣
r
∣
2
=
a
2
+
b
2
−
2
ab
cos
θ
. b. (ii) Using the result from part (i), compute
∣
r
∣
|\mathbf{r}|
∣
r
∣
when
a
=
12
a=12
a
=
12
,
b
=
9
b=9
b
=
9
and
θ
=
150
∘
\theta=150^{\circ}
θ
=
15
0
∘
.
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