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Problem
Problem
- If
3
(
a
+
2
c
)
=
4
(
b
+
3
d
)
≠
0
3(a+2c) = 4(b+3d) \ne 0
3
(
a
+
2
c
)
=
4
(
b
+
3
d
)
=
0
, then the equation
a
x
3
+
b
x
2
+
c
x
+
d
=
0
ax^3 + bx^2 + cx + d = 0
a
x
3
+
b
x
2
+
c
x
+
d
=
0
will have a. no real solution b. atleast one real root in
(
−
1
,
0
)
(-1, 0)
(
−
1
,
0
)
c. atleast one real root in
(
0
,
1
)
(0, 1)
(
0
,
1
)
d. None of the above
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