Mathematics

Mathematics

Problem

Let p(x)=x+2x3−4xp(x)=\dfrac{x+2}{x^{3}-4x}, where pp is defined for all xx in its domain. Which statement correctly describes the locations of the vertical asymptotes of pp and the corresponding one-sided limits? a) Vertical asymptotes at x=0x=0 and x=2x=2; p(x)→−∞p(x)\to -\infty as x→0−, 2+x\to 0^{-},\,2^{+} and p(x)→+∞p(x)\to +\infty as x→0+, 2−x\to 0^{+},\,2^{-}. b) Vertical asymptotes at x=0x=0 and x=2x=2; p(x)→+∞p(x)\to +\infty as x→0−, 2+x\to 0^{-},\,2^{+} and p(x)→−∞p(x)\to -\infty as x→0+, 2−x\to 0^{+},\,2^{-}. c) Vertical asymptotes at x=−2, 0, 2x=-2,\,0,\,2; p(x)→+∞p(x)\to +\infty on the right of each asymptote and −∞-\infty on the left. d) Vertical asymptotes at x=0x=0 and x=2x=2; p(x)→+∞p(x)\to +\infty on both sides of each asymptote.

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