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Mathematics
Problem
The maximum value of
3
cos
θ
+
5
sin
(
θ
−
π
6
)
3\cos\theta + 5\sin\left(\theta - \frac{\pi}{6}\right)
3
cos
θ
+
5
sin
(
θ
−
6
π
)
for any real value of
θ
\theta
θ
is : [JEE-MAIN ONLINE-2019] (1)
19
\sqrt{19}
19
(2)
79
2
\frac{\sqrt{79}}{2}
2
79
(3)
31
\sqrt{31}
31
(4)
34
\sqrt{34}
34
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