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Physics
Physics
Problem
An experiment traps exactly
N
=
6.10
×
10
22
N=6.10\times10^{22}
N
=
6.10
×
1
0
22
molecules of an ideal gas in a
2.50
L
2.50\,\text{L}
2.50
L
vessel at
T
=
295
K
T=295\,\text{K}
T
=
295
K
. The pressure is
1.05
×
10
5
Pa
1.05\times10^{5}\,\text{Pa}
1.05
×
1
0
5
Pa
. Using
N
A
=
6.022
×
10
23
mol
−
1
N_{\!A}=6.022\times10^{23}\,\text{mol}^{-1}
N
A
=
6.022
×
1
0
23
mol
−
1
and
k
B
=
1.38
×
10
−
23
J
K
−
1
k_{B}=1.38\times10^{-23}\,\text{J}\,\text{K}^{-1}
k
B
=
1.38
×
1
0
−
23
J
K
−
1
, calculate the value of
R
R
R
obtained from this trial, in
J
(
mol
⋅
K
)
\text{J}\,(\text{mol}\cdot\text{K})
J
(
mol
⋅
K
)
.
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