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Problem
Problem
Solution of inequality
∣
x
+
3
∣
>
∣
2
x
−
1
∣
|x + 3| > |2x - 1|
∣
x
+
3∣
>
∣2
x
−
1∣
is a.
(
2
−
3
,
2
+
3
)
∪
(
−
2
−
3
,
−
2
+
3
)
(2 - \sqrt{3}, 2 + \sqrt{3}) \cup (-2 - \sqrt{3}, -2 + \sqrt{3})
(
2
−
3
,
2
+
3
)
∪
(
−
2
−
3
,
−
2
+
3
)
b.
R
−
(
2
−
3
,
2
+
3
)
R - (2 - \sqrt{3}, 2 + \sqrt{3})
R
−
(
2
−
3
,
2
+
3
)
c.
R
−
(
−
2
−
3
,
2
+
3
)
R - (-2 - \sqrt{3}, 2 + \sqrt{3})
R
−
(
−
2
−
3
,
2
+
3
)
d. None of the above
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