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Mathematics
Mathematics
Problem
Which of the following gives the general solution of the equation
sin
θ
=
sin
α
\sin\theta = \sin\alpha
sin
θ
=
sin
α
? a)
θ
=
2
n
π
±
α
,
n
∈
Z
\theta = 2n\pi \pm \alpha,\; n\in\mathbb{Z}
θ
=
2
nπ
±
α
,
n
∈
Z
b)
θ
=
n
π
+
(
−
1
)
n
α
,
n
∈
Z
\theta = n\pi + (-1)^n\alpha,\; n\in\mathbb{Z}
θ
=
nπ
+
(
−
1
)
n
α
,
n
∈
Z
c)
θ
=
n
π
+
α
,
n
∈
Z
\theta = n\pi + \alpha,\; n\in\mathbb{Z}
θ
=
nπ
+
α
,
n
∈
Z
d)
θ
=
n
π
±
α
,
n
∈
Z
\theta = n\pi \pm \alpha,\; n\in\mathbb{Z}
θ
=
nπ
±
α
,
n
∈
Z
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