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Mathematics
Problem
Let
ω
\omega
ω
be a complex number such that
2
ω
+
1
=
z
2\omega + 1 = z
2
ω
+
1
=
z
, when
z
=
−
3
z = \sqrt{-3}
z
=
−
3
if
∣
1
1
1
1
−
ω
2
−
1
ω
2
1
ω
2
ω
7
∣
=
3
k
\begin{vmatrix} 1 & 1 & 1 \\ 1 & -\omega^2 - 1 & \omega^2 \\ 1 & \omega^2 & \omega^7 \end{vmatrix} = 3k
1
1
1
1
−
ω
2
−
1
ω
2
1
ω
2
ω
7
=
3
k
, then
k
k
k
is equal to a. 1 b.
−
z
-z
−
z
c.
z
z
z
d.
−
1
-1
−
1
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