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Mathematics
Mathematics
Problem
For the curve
x
=
t
3
−
3
t
,
y
=
t
2
x=t^{3}-3t,\; y=t^{2}
x
=
t
3
−
3
t
,
y
=
t
2
, determine the nature of the tangent at the point corresponding to
t
=
1
t=1
t
=
1
. a) Horizontal tangent (slope
=
0
=0
=
0
) b) Slope
=
2
3
=\dfrac{2}{3}
=
3
2
c) Vertical tangent d) Slope
=
−
1
=-1
=
−
1
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