Consider blackbody radiation at a temperature T. Show that for an energy threshold E0≫kT, the fraction of the blackbody photons that have energy hf>E0 is
nγn(hf>E0)≈0.42(kTE0)2exp(−kTE0).(2.43)
The cosmic background radiation is currently called the ``cosmic microwave background.'' However, photons with λ<1mm actually lie in the far infrared range of the electromagnetic spectrum. It's time for truth in advertising: what fraction of the photons in today's ``cosmic microwave background'' are actually far infrared photons?