Mathematics

Mathematics

Problem

A function gg satisfies lim⁡x→3−g(x)−g(3)x−3=4\lim_{x\to 3^-}\frac{g(x)-g(3)}{x-3}=4 and lim⁡x→3+g(x)−g(3)x−3=−1\lim_{x\to 3^+}\frac{g(x)-g(3)}{x-3}=-1. Which statement about gg at x=3x=3 is true? a) gg is differentiable at x=3x=3 with g′(3)=32g'(3)=\frac{3}{2}. b) gg is not differentiable at x=3x=3 because the one-sided limits are unequal. c) gg is differentiable at x=3x=3 with g′(3)=−1g'(3)=-1. d) gg is not continuous at x=3x=3 because the one-sided limits are unequal.

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