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Mathematics
Mathematics
Problem
P is a point on AL, the altitude of the triangle ABC through A. If
∠
P
B
A
=
20
∘
\angle PBA = 20^\circ
∠
P
B
A
=
2
0
∘
,
∠
P
B
C
=
40
∘
\angle PBC = 40^\circ
∠
P
B
C
=
4
0
∘
and
∠
P
C
B
=
30
∘
\angle PCB = 30^\circ
∠
P
C
B
=
3
0
∘
, then
∠
P
C
A
\angle PCA
∠
P
C
A
equals
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