Problem

Problem

FeCl3\text{FeCl}_3 solution added to K4[Fe(CN)6]\text{K}_4[\text{Fe}(\text{CN})_6] gives A while with KSCN gives B. A and B respectively are : a. Fe3[Fe(CN)6]2,Fe(CNS)3\text{Fe}_3[\text{Fe}(\text{CN})_6]_2, \text{Fe}(\text{CNS})_3 b. Fe4[Fe(CN)6]3,KFe(CNS)3\text{Fe}_4[\text{Fe}(\text{CN})_6]_3, \text{KFe}(\text{CNS})_3 c. Fe4[Fe(CN)6]3,K3[Fe(CNS)6]\text{Fe}_4[\text{Fe}(\text{CN})_6]_3, \text{K}_3[\text{Fe}(\text{CNS})_6] d. Fe4[Fe(CN)6]3,K3[Fe(SCN)6]\text{Fe}_4[\text{Fe}(\text{CN})_6]_3, \text{K}_3[\text{Fe}(\text{SCN})_6]

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