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Mathematics
Problem
If
x
=
2
t
+
1
x=2t+1
x
=
2
t
+
1
and
y
=
3
t
2
−
5
y=3t^{2}-5
y
=
3
t
2
−
5
, the equation of the tangent to the curve at
t
=
2
t=2
t
=
2
is: a)
y
=
6
x
+
23
y = 6x + 23
y
=
6
x
+
23
b)
y
=
12
x
−
53
y = 12x - 53
y
=
12
x
−
53
c)
y
=
6
x
−
23
y = 6x - 23
y
=
6
x
−
23
d)
y
=
6
x
−
5
y = 6x - 5
y
=
6
x
−
5
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