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Problem
Problem
- Let
2
sin
2
x
+
3
sin
x
−
2
>
0
2\sin^2 x + 3\sin x - 2 > 0
2
sin
2
x
+
3
sin
x
−
2
>
0
and
x
2
−
x
−
2
<
0
x^2 - x - 2 < 0
x
2
−
x
−
2
<
0
(
x
x
x
is measured in radian). Then '
x
x
x
' lies in the interval. a.
(
π
6
,
5
π
6
)
\left(\frac{\pi}{6}, \frac{5\pi}{6}\right)
(
6
π
,
6
5
π
)
b.
(
−
1
,
5
π
6
)
\left(-1, \frac{5\pi}{6}\right)
(
−
1
,
6
5
π
)
c.
(
−
1
,
2
)
(-1, 2)
(
−
1
,
2
)
d.
(
π
6
,
2
)
\left(\frac{\pi}{6}, 2\right)
(
6
π
,
2
)
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