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Mathematics
Problem
If
∣
z
−
2
i
∣
≤
2
|z - 2i| \le \sqrt{2}
∣
z
−
2
i
∣
≤
2
, where
i
=
−
1
i = \sqrt{-1}
i
=
−
1
, then the maximum value of
∣
3
−
i
(
z
−
1
)
∣
|3 - i(z - 1)|
∣3
−
i
(
z
−
1
)
∣
, is a.
2
\sqrt{2}
2
b.
2
2
2\sqrt{2}
2
2
c.
2
+
2
2 + \sqrt{2}
2
+
2
d.
3
+
2
2
3 + 2\sqrt{2}
3
+
2
2
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