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Mathematics
Problem
The point of intersection of the line
x
−
1
3
=
y
+
2
4
=
z
−
3
−
2
\frac{x-1}{3} = \frac{y+2}{4} = \frac{z-3}{-2}
3
x
−
1
=
4
y
+
2
=
−
2
z
−
3
and plane
2
x
−
y
+
3
z
−
1
=
0
2x - y + 3z - 1 = 0
2
x
−
y
+
3
z
−
1
=
0
is
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