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Chemistry
Chemistry
Problem
Find out the energy of H atom in first excitation state. The value of permittivity factor
4
π
ϵ
0
=
1.11264
×
10
−
10
C
2
N
−
1
m
−
2
4\pi\epsilon_0 = 1.11264 \times 10^{-10} \text{ C}^2 \text{ N}^{-1} \text{ m}^{-2}
4
π
ϵ
0
=
1.11264
×
1
0
−
10
C
2
N
−
1
m
−
2
.
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