Mathematics

Mathematics

Problem

ddx[(1+x2)tan⁡−1x]=\frac{d}{dx} [(1 + x^2) \tan^{-1} x] = (a) xtan⁡−1xx \tan^{-1} x (b) 2tan⁡−1x2 \tan^{-1} x (c) 2xtan⁡−1x+12x \tan^{-1} x + 1 (d) xtan⁡−1x+1x \tan^{-1} x + 1

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