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Mathematics
Mathematics
Problem
Let
sin
θ
=
3
5
\sin\theta=\dfrac{3}{5}
sin
θ
=
5
3
where
π
2
<
θ
<
π
\dfrac{\pi}{2}<\theta<\pi
2
π
<
θ
<
π
. a. (i) Calculate
cos
θ
\cos\theta
cos
θ
and
tan
θ
\tan\theta
tan
θ
. b. (ii) Find
sin
2
θ
\sin 2\theta
sin
2
θ
,
cos
2
θ
\cos 2\theta
cos
2
θ
and
tan
2
θ
\tan 2\theta
tan
2
θ
. c. (iii) Hence compute the value of
sin
2
θ
+
cos
2
θ
tan
2
θ
\dfrac{\sin 2\theta+\cos 2\theta}{\tan 2\theta}
tan
2
θ
sin
2
θ
+
cos
2
θ
, simplifying your answer.
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