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Mathematics
Problem
The function
f
:
R
∖
{
−
2
}
→
R
f:\mathbb{R}\setminus\{-2\}\to\mathbb{R}
f
:
R
∖
{
−
2
}
→
R
given by
f
(
x
)
=
a
x
+
1
x
+
2
f(x)=\dfrac{ax+1}{x+2}
f
(
x
)
=
x
+
2
a
x
+
1
is one–one on its domain if and only if a)
a
>
1
2
a>\dfrac12
a
>
2
1
b)
a
≠
1
2
a\neq\dfrac12
a
=
2
1
c)
a
=
1
2
a=\dfrac12
a
=
2
1
d)
a
<
1
2
a<\dfrac12
a
<
2
1
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