Physics

Physics

Problem

An atom absorbs a photon of wavelength 500 nm and emits another photon of wavelength 600 nm. The net energy absorbed by the atom in this process is n×10−4n \times 10^{-4} eV. The value of nn is [Assume the atom to be stationary during the absorption and emission process] (Take h=6.6×10−34h = 6.6 \times 10^{-34} J s and c=3×108c = 3 \times 10^8 m s−1s^{-1} ).

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