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Physics
Physics
Problem
A proton possessing kinetic energy
2.0
keV
2.0\,\text{keV}
2.0
keV
moves perpendicular to a uniform magnetic field of magnitude
0.04
T
0.04\,\text{T}
0.04
T
. Calculate the radius of the circular path followed by the proton. (Take
e
=
1.6
×
10
−
19
C
e = 1.6\times10^{-19}\,\text{C}
e
=
1.6
×
1
0
−
19
C
,
m
p
=
1.67
×
10
−
27
kg
m_{p}=1.67\times10^{-27}\,\text{kg}
m
p
=
1.67
×
1
0
−
27
kg
.)
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