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Problem Without using a calculator, find:
a) sin θ \sin \theta sin θ cos θ = 2 3 \cos \theta = \frac{2}{3} cos θ = 3 2 0 < θ < π 2 0 < \theta < \frac{\pi}{2} 0 < θ < 2 π cos θ \cos \theta cos θ sin θ = 2 5 \sin \theta = \frac{2}{5} sin θ = 5 2 π 2 < θ < π \frac{\pi}{2} < \theta < \pi 2 π < θ < π cos θ \cos \theta cos θ sin θ = − 3 5 \sin \theta = -\frac{3}{5} sin θ = − 5 3 3 π 2 < θ < 2 π \frac{3\pi}{2} < \theta < 2\pi 2 3 π < θ < 2 π sin θ \sin \theta sin θ cos θ = − 5 13 \cos \theta = -\frac{5}{13} cos θ = − 13 5 π < θ < 3 π 2 \pi < \theta < \frac{3\pi}{2} π < θ < 2 3 π Browse the problem library