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Physics
Physics
Problem
A voltage
v
=
v
0
sin
ω
t
v = v_0 \sin \omega t
v
=
v
0
sin
ω
t
applied to a circuit drives a current
i
=
i
0
sin
(
ω
t
+
ϕ
)
i = i_0 \sin (\omega t + \phi)
i
=
i
0
sin
(
ω
t
+
ϕ
)
in the circuit. The average power consumed in the circuit over a cycle is (A) Zero (B)
i
0
v
0
cos
ϕ
i_0 v_0 \cos \phi
i
0
v
0
cos
ϕ
(C)
i
0
v
0
2
\frac{i_0 v_0}{2}
2
i
0
v
0
(D)
i
0
v
0
2
cos
ϕ
\frac{i_0 v_0}{2} \cos \phi
2
i
0
v
0
cos
ϕ
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