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Mathematics
Problem
A particle moves with velocity
v
(
t
)
=
3
t
2
+
2
k
v(t)=3t^{2}+2k
v
(
t
)
=
3
t
2
+
2
k
for
t
≥
0
t\ge 0
t
≥
0
. Its position satisfies
s
(
0
)
=
2
s(0)=2
s
(
0
)
=
2
and
s
(
2
)
=
18
s(2)=18
s
(
2
)
=
18
. What is the value of the constant
k
k
k
? a)
k
=
−
2
k=-2
k
=
−
2
b)
k
=
5
2
k=\dfrac{5}{2}
k
=
2
5
c)
k
=
2
k=2
k
=
2
d)
k
=
4
k=4
k
=
4
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