Mathematics

Mathematics

Problem

If the midpoint of a chord of the ellipse x29+y24=1\frac{x^2}{9} + \frac{y^2}{4} = 1 is (2,4/3)(\sqrt{2}, 4/3) , and the length of the chord is 2α3\frac{2\sqrt{\alpha}}{3} , then α\alpha is :

Browse the problem library