Mathematics

Mathematics

Problem

Consider the improper integral ∫031(x−1)2 dx\displaystyle\int_{0}^{3}\frac{1}{(x-1)^2}\,dx. Which of the following is true? a) The integral diverges because the integrand has a vertical asymptote at x=1x=1, so no finite value exists. b) The integral converges and equals 11. c) The integral diverges because the integrand is unbounded at x=0x=0. d) The integral converges and equals 32\dfrac{3}{2}.

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