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Problem
Calculate the mass of magnesium sulfide that can be obtained from the reaction between 4.862 g of magnesium and 3.207 g of sulfur.
Mg(s)
+
S(s)
→
MgS(s)
\text{Mg(s)} + \text{S(s)} \rightarrow \text{MgS(s)}
Mg(s)
+
S(s)
→
MgS(s)
Identify the limiting reactant and calculate the mass of the unreacted element present in excess.
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