General Relativity: An Introduction for Physicists · Problem 9.26

The Schwarzschild geometry — Hobson, Efstathiou & Lasenby

Physics · particle-antiparticle-annihilation-schwarzschild

Problem

A particle AA and its antiparticle BB are travelling in opposite senses in free circular orbits in the equatorial plane of the Schwarzschild geometry, one at coordinate radius rAr_A and the other at rB(>rA)r_B (> r_A). At some instant, AA emits a photon of frequency νA\nu_A that travels radially and is received by BB with frequency νB\nu_B. Show that νBνA=(1−3μ/rA1−3μ/rB)1/2.\frac{\nu_B}{\nu_A} = \left(\frac{1-3\mu/r_A}{1-3\mu/r_B}\right)^{1/2}. Suppose now that rA=rB=rr_A = r_B = r, so that the particles collide and annihilate each other. Show that the total radiated energy as measured by an observer at rest at the point of collision is given by E=2m0c2(1−2μ/r1−3μ/r)1/2,E = 2m_0 c^2 \left(\frac{1-2\mu/r}{1-3\mu/r}\right)^{1/2}, where m0m_0 is the rest mass of each particle.

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