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Mathematics
Problem
The expression
(
1
+
i
tan
α
1
−
i
tan
α
)
n
−
1
+
i
tan
n
α
1
−
i
tan
n
α
\left(\frac{1+i\tan\alpha}{1-i\tan\alpha}\right)^n - \frac{1+i\tan n\alpha}{1-i\tan n\alpha}
(
1
−
i
t
a
n
α
1
+
i
t
a
n
α
)
n
−
1
−
i
t
a
n
n
α
1
+
i
t
a
n
n
α
when simplified reduces to : (1) zero (2)
2
sin
n
α
2 \sin n\alpha
2
sin
n
α
(3)
2
cos
n
α
2 \cos n\alpha
2
cos
n
α
(4) none of these
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