Mathematics

Mathematics

Problem

If twice the square of the diameter of a circle is equal to sum of the squares of the sides of the inscribed triangle ABC, then sin⁡2A+sin⁡2B+sin⁡2C\sin^2 A + \sin^2 B + \sin^2 C is equal to (a) 2 (b) 3 (c) 4 (d) 1

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