Equation of any plane containing the line ax−x1=by−y1=cz−z1 is A(x−x1)+B(y−y1)+C(z−z1)=0 , then pick correct alternatives
a. aA=bB=cC is true for the line to be perpendicular to the plane
b. A(a+3)+B(b−1)+C(c−2)=0
c. 2aA+3bB+4cC=0
d. Aa+Bb+Cc=0