A 4.00 g impure sample of KOH is dissolved in water and diluted to exactly 250.0 mL. A 25.00 mL aliquot of this solution requires 24.60 mL of 0.200 M HCl to reach the equivalence point.
KOH(aq)+HCl(aq)→KCl(aq)+H2O(ℓ)
What is the percent purity of KOH in the original solid sample?
a) 48.1%
b) 69.0%
c) 6.90%
d) 34.5%