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Mathematics
Mathematics
Problem
Prove that
9
π
8
−
9
4
sin
−
1
1
3
=
9
4
sin
−
1
2
2
3
.
\frac{9\pi}{8} - \frac{9}{4} \sin^{-1} \frac{1}{3} = \frac{9}{4} \sin^{-1} \frac{2\sqrt{2}}{3}.
8
9
π
−
4
9
sin
−
1
3
1
=
4
9
sin
−
1
3
2
2
.
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