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Mathematics
Problem
The limaçon
r
=
1
+
2
cos
θ
r=1+2\cos\theta
r
=
1
+
2
cos
θ
has a small inner loop. What is the area enclosed by this inner loop? a)
2
π
−
3
3
2\pi-3\sqrt3
2
π
−
3
3
b)
3
−
π
3
\sqrt3-\dfrac{\pi}{3}
3
−
3
π
c)
π
−
3
3
2
\displaystyle \pi-\dfrac{3\sqrt3}{2}
π
−
2
3
3
d)
π
2
−
3
3
4
\displaystyle \frac{\pi}{2}-\frac{3\sqrt3}{4}
2
π
−
4
3
3
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