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Physics
Physics
Problem
Calculate the altitude above Earth’s surface of a satellite that remains fixed over one point on the equator. Take
M
⊕
=
6.0
×
10
24
kg
M_{\oplus}=6.0\times10^{24}\,\text{kg}
M
⊕
=
6.0
×
1
0
24
kg
,
R
⊕
=
6.4
×
10
6
m
R_{\oplus}=6.4\times10^{6}\,\text{m}
R
⊕
=
6.4
×
1
0
6
m
,
G
=
6.67
×
10
−
11
N
m
2
kg
−
2
G=6.67\times10^{-11}\,\text{N\,m}^{2}\text{kg}^{-2}
G
=
6.67
×
1
0
−
11
N
m
2
kg
−
2
and Earth’s rotation period
T
=
24
h
T=24\,\text{h}
T
=
24
h
.
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