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Problems
If
∫
2
cos
x
−
sin
x
+
λ
cos
x
+
sin
x
−
2
d
x
=
A
ln
∣
cos
x
+
sin
x
−
2
∣
+
B
x
+
c
\int \frac{2 \cos x - \sin x + \lambda}{\cos x + \sin x - 2}\,dx = A \ln|\cos x + \sin x - 2| + Bx + c
∫
c
o
s
x
+
s
i
n
x
−
2
2
c
o
s
x
−
s
i
n
x
+
λ
d
x
=
A
ln
∣
cos
x
+
sin
x
−
2∣
+
B
x
+
c
…
Mathematics
Problem
If
∫
2
cos
x
−
sin
x
+
λ
cos
x
+
sin
x
−
2
d
x
=
A
ln
∣
cos
x
+
sin
x
−
2
∣
+
B
x
+
c
\int \frac{2 \cos x - \sin x + \lambda}{\cos x + \sin x - 2}\,dx = A \ln|\cos x + \sin x - 2| + Bx + c
∫
c
o
s
x
+
s
i
n
x
−
2
2
c
o
s
x
−
s
i
n
x
+
λ
d
x
=
A
ln
∣
cos
x
+
sin
x
−
2∣
+
B
x
+
c
then
A
+
B
+
∣
λ
∣
=
A + B + |\lambda| =
A
+
B
+
∣
λ
∣
=
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