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If
sin
−
1
(
x
5
)
+
csc
−
1
(
5
4
)
=
π
2
\sin^{-1} \left( \frac{x}{5} \right) + \csc^{-1} \left( \frac{5}{4} \right) = \frac{\pi}{2}
sin
−
1
(
5
x
)
+
csc
−
1
(
4
5
)
=
2
π
…
Problem
If
sin
−
1
(
x
5
)
+
csc
−
1
(
5
4
)
=
π
2
\sin^{-1} \left( \frac{x}{5} \right) + \csc^{-1} \left( \frac{5}{4} \right) = \frac{\pi}{2}
sin
−
1
(
5
x
)
+
csc
−
1
(
4
5
)
=
2
π
, then the value of
x
x
x
is a. 1 b. 3 c. 4 d. 5
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