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Mathematics
Mathematics
Problem
Prove that
1
−
tan
2
(
π
4
−
A
)
1
+
tan
2
(
π
4
−
A
)
=
sin
2
A
\frac{1 - \tan^2\left(\frac{\pi}{4} - A\right)}{1 + \tan^2\left(\frac{\pi}{4} - A\right)} = \sin 2A
1
+
t
a
n
2
(
4
π
−
A
)
1
−
t
a
n
2
(
4
π
−
A
)
=
sin
2
A
.
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