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Mathematics
Problem
A unit vector has components proportional to
2
,
−
3
,
4
2,-3,4
2
,
−
3
,
4
. If the vector lies in the region where
x
>
0
x>0
x
>
0
and
z
>
0
z>0
z
>
0
, determine the proportionality constant
k
k
k
such that its components are
(
2
k
,
−
3
k
,
4
k
)
(2k,-3k,4k)
(
2
k
,
−
3
k
,
4
k
)
. a)
k
=
−
1
29
k=-\dfrac{1}{\sqrt{29}}
k
=
−
29
1
b)
k
=
1
29
k=\dfrac{1}{29}
k
=
29
1
c)
k
=
1
29
k=\dfrac{1}{\sqrt{29}}
k
=
29
1
d)
k
=
29
k=\sqrt{29}
k
=
29
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