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Mathematics
Mathematics
Problem
Given
sin
x
=
3
5
\sin x=\dfrac{3}{5}
sin
x
=
5
3
with
0
∘
<
x
<
90
∘
0^{\circ}<x<90^{\circ}
0
∘
<
x
<
9
0
∘
, find the value of
cos
2
x
\cos 2x
cos
2
x
. a)
−
7
25
-\dfrac{7}{25}
−
25
7
b)
16
25
\dfrac{16}{25}
25
16
c)
7
25
\dfrac{7}{25}
25
7
d)
24
25
\dfrac{24}{25}
25
24
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