Problem

Problem

A rope of length LL and mass MM is being pulled on a rough horizontal floor by a constant horizontal force F=MgF = Mg. The force is acting at one end of the rope in the same direction as the length of the rope. The coefficient of kinetic friction between rope and floor is 1/21/2. Then, the tension at the midpoint of the rope is a. Mg4\frac{Mg}{4} b. 2Mg5\frac{2Mg}{5} c. Mg8\frac{Mg}{8} d. Mg2\frac{Mg}{2}

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