Chemistry

Chemistry

Problem

A graph plotted between PdPd vs. PP where PP is pressure of C2H6C_2H_6 gas (assume ideal gas) and dd is its density in g/L at particular temperature [dPddP]=20\left[ \frac{dPd}{dP} \right] = 20 when P=8.21P = 8.21 atm, the temperature of gas will be : a. 400 K b. 1200 K c. 300 K d. 600 K

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