Physics

Physics

Problem

A particle of mass mm is moving in the xyxy-plane such that its velocity at a point (x,y)(x, y) is given as v⃗=α(yx^+2xy^)\vec{v} = \alpha(y\hat{x} + 2x\hat{y}), where α\alpha is a non-zero constant. What is the force F⃗\vec{F} acting on the particle? [Adv. 2023] (a) F⃗=2mα2(xx^+yy^)\vec{F} = 2m\alpha^2(x\hat{x} + y\hat{y}) (b) F⃗=mα2(yx^+2xy^)\vec{F} = m\alpha^2(y\hat{x} + 2x\hat{y}) (c) F⃗=2mα2(yx^+xy^)\vec{F} = 2m\alpha^2(y\hat{x} + x\hat{y}) (d) F⃗=mα2(xx^+2yy^)\vec{F} = m\alpha^2(x\hat{x} + 2y\hat{y})

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