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Mathematics
Mathematics
Problem
The distance of the point
P
(
−
2
,
3
,
−
4
)
P(-2, 3, -4)
P
(
−
2
,
3
,
−
4
)
from the line
x
+
2
3
=
2
y
+
3
4
=
3
z
+
4
5
\frac{x+2}{3} = \frac{2y+3}{4} = \frac{3z+4}{5}
3
x
+
2
=
4
2
y
+
3
=
5
3
z
+
4
measured parallel to the plane
4
x
+
12
y
−
3
z
+
1
=
0
4x + 12y - 3z + 1 = 0
4
x
+
12
y
−
3
z
+
1
=
0
is
d
d
d
, then find the value of
(
2
d
−
8
)
(2d - 8)
(
2
d
−
8
)
.
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