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Problems
Problem
Problem
Solve
log
4
(
log
3
x
)
+
log
1
/
4
(
log
1
/
3
y
)
=
0
\log_4(\log_3 x) + \log_{1/4}(\log_{1/3} y) = 0
lo
g
4
(
lo
g
3
x
)
+
lo
g
1/4
(
lo
g
1/3
y
)
=
0
and
x
2
+
y
2
=
17
4
.
x^2 + y^2 = \frac{17}{4}.
x
2
+
y
2
=
4
17
.
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