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Mathematics
Mathematics
Problem
Prove that
tan
θ
cot
(
90
∘
−
θ
)
+
sin
2
θ
+
cos
2
θ
=
sec
2
θ
\tan \theta\; \cot(90^{\circ} - \theta) + \sin^{2}\theta + \cos^{2}\theta = \sec^{2}\theta
tan
θ
cot
(
9
0
∘
−
θ
)
+
sin
2
θ
+
cos
2
θ
=
sec
2
θ
for all acute angles
θ
\theta
θ
.
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