Chemistry

Chemistry

Problem

A reaction has Kc=0.35K_c = 0.35 at a given temperature. If every stoichiometric coefficient in the balanced equation is divided by 2, how will the new equilibrium constant Kc′K_c' compare with 0.35? a) Kc′=10.35K_c' = \dfrac{1}{\sqrt{0.35}} b) Kc′=(0.35)2K_c' = (0.35)^2 c) Kc′=0.35K_c' = \sqrt{0.35} d) Kc′=10.35K_c' = \dfrac{1}{0.35}

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